How to group from file by some condition or get count of unique data

For example you have file which contains log of some events.

Input data:

Dec  9 00:33:42 some log
Dec  9 00:56:49 some log
Dec  9 01:13:12 some log
Dec  9 01:22:02 some log
Dec  9 01:35:52 some log
Dec  9 03:15:52 some log
Dec  9 12:17:52 some log


And you want group this file by hours. The code below will help group and display data:


grep -oP "Dec\s+9\s(\d{2})" | sort | uniq -c



 Output data:


2 Dec 9 00
3 Dec 9 01
1 Dec 9 03
1 Dec 9 12

First column - it's count of unique lines with the date.

Flag -o is required to output only the requested substring (Dec\s+9\s(\d{2}))
Flag -P is required for enable perl-style regexes

Command sort sorts the data.
And uniq -c find count of unique lines.

Thank you for reading. Best regards, Ildar.

Комментарии

Популярные сообщения из этого блога

Как преобразовать строку в массив в ClickHouse / How to transform string to array in ClickHouse

Как разложить массив на несколько строк в ClickHouse

Экспорт одной таблицы базы данных или mysqldump одной таблицы (MySQL)